Question

Q13.How many moles of Al2O3 will be formed when a mixture of 5.4 g of Al and 3.2 g of O2 is heated ?

Answer 1

Answer:

0.066 mole

Explanation:

Answer 2

Answer:

From the equation we know that 4Al + 3O2 -> 2Al2O3.

We know that the moles of aluminium = 5.4/27 = 0.1 mole.

Moles of oxygen gas = 3.2/(16*2) = 0.1 mole.

So, from the reaction we get 4 moles of Aluminium reacts with 3 moles of oxygen.

From the equation we know that 0.2 mol of aluminum will react with:

We get that 3/4*0.2 = 0.15 mol of the  oxygen gas.

Consequently 0.1 mol of oxygen will react with:

So, we get that 4/3*0.1=0.13 mol of aluminum.

We can conclude that oxygen is the limiting reagent.

Since we know that 2 moles oxygen gives 3 moles Al2O3 then 0.1 moles of oxygen will give 2/3*0.1= 0.066 of aluminum oxide.