Q13) How many three digit
numbers are divisible by 7.
130
129
128
127
Answers
Answered by
2
Answer:
lowest 3 digit no. divisible by 7 = 105 = a
highest 3 digit no. divisible by 7 = 994 = an
D = 7
an = a+ (n-1) d
994 = 105 + (n-1) 7
889/7 = n-1
127 +1 = n
or n = 128
THUS UR ANS IS 128
Answered by
2
Answer:
The last 3 digit number divisible by 7 is 994 Using the formula T(nth term) = a + (n-1)d, we have 994 = 105+(n-1)7 7(n-1) = 889 n-1 = 127 n = 128.
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