Question

Q13) How many three digit
numbers are divisible by 7.
130
129

128
127​

Answer 1

Answer:

lowest 3 digit no. divisible by 7 = 105 = a

highest 3 digit no. divisible by 7 = 994 = an

D = 7

an = a+ (n-1) d

994 = 105 + (n-1) 7

889/7 = n-1

127 +1 = n

or n = 128

THUS UR ANS IS 128

Answer 2

Answer:

The last 3 digit number divisible by 7 is 994 Using the formula T(nth term) = a + (n-1)d, we have 994 = 105+(n-1)7 7(n-1) = 889 n-1 = 127 n = 128.