Math, asked by snehamurmu995, 3 months ago

Q13) in a cricket match, a batswoman hits a boundary 25 tites out of 60 balls she plays. Find
the probability that she did not hit a boundary. What is the sum of the probability that she hit a
boundary and the probability that she didn't hit a boundary?​

Answers

Answered by Saby123
107

Answer:

The required probability is 1 .

Step-by-step explanation:

In any event , the sum of P(A) and P'(A) is always 1 .

Here , in a cricket match , the batswoman hits a boundary 25 times out of the 60 balls she plays .

The total number of balls ( Sample Space ) 60

Favourable Cases ( The no of times she hit a boundary ) > 25

Unfavourable Cases > 35

Probability that she hit a boundary > 25/60

Probability that she didn't hit a boundary > 35/60

Probability that she hit a boundary + Probability that she didn't hit a boundary

> 25/60 + 35/60

> 60/60

> 1

Additional Information :

 \boxed {\begin{minipage}{9.2 cm}\\  \dag \: \underline{\Large\bf Formulas\:of\:Statistics} \\ \\ \bigstar \: \underline{\rm Mean:} \\ \\ \bullet\sf M=\dfrac {\Sigma x}{n} \\ \bullet\sf M=a+\dfrac {\Sigma fy}{\Sigma f} \\ \\ \bullet\sf M=A +\dfrac {\Sigma fy^i}{\Sigma f}\times c \\ \\ \bigstar \: \underline{\rm Median :} \\ \\ \bullet\sf M_d=\dfrac {n+1}{2} \:\left[\because n\:is\:odd\:number\right] \\ \bullet\sf M_d=\dfrac {1}{2}\left (\dfrac {n}{2}+\dfrac {n}{2}+1\right)\:\left[\because n\:is\:even\:number\right] \\ \\ \bullet\sf M_d=l+\dfrac {m-c}{f}\times i \\ \\ \bigstar \: {\boxed{\sf M_0=3M_d-2M}}\end {minipage}}

Answered by VinCus
142

Given:-

▪︎In a cricket match , a bastswoman hits a boundary 25 tites out of 60 balls she plays.

To Find:-

▪︎The probability that she did not hit a boundary?

▪︎Sum of the probability that she hit a boundary and didn't hit a boundary?

Solution:-

Probability that she did not hit the boundary:

 \\  \dashrightarrow \sf  \frac{60 - 25}{60}  =   \frac{35}{60}   \implies \frac{7}{12}

 \\  \dashrightarrow { \boxed{\sf{ Probability \:  that \:  she \:  didn't \:  hit \:  the \:  boundary =   \frac{7}{12} }}}

The sum of Probability that she hit a boundary and didn't hit a boundary:

   \star{\underbrace{ \boxed{ \boxed{ \sf{Sum  \: of  \: the \:  probability = No \:  of  \: boundary \:  she \:  hits + No  \: of  \: boundary  \: she  \: didn't \:  hit}}}}} \star

 \\  \dashrightarrow \sf  Sum  \: of \:  the \:  probability =   \left(\frac{7}{12}  +  \frac{25}{60}  \right)

 \\  \dashrightarrow \sf  Sum  \: of \:  the \:  probability =   \left(\frac{7}{12}  +  \frac{5}{12}  \right)

 \\  \dashrightarrow \sf  Sum  \: of \:  the \:  probability =   \left(\frac{12}{12} \right)

 \\  \dashrightarrow { \boxed{\sf{ Sum  \: of \:  the \:  probability =  1}}}

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