Math, asked by sumit56838, 3 months ago

Q13. On birthday party of Palak, a cake was cut and eaten up.
Jiya ate 1/6 of the cake,
Tanisha ate 1/5 of what was left,
Trisha ate 1/4 of what remained,
Karishmita ate the 1/3 of remaining share,
At the end of party, Palak and Aabha shared the last piece equally.​

Answers

Answered by sshakuntala1977
1

Answer:

Let the cake be = x

Jiya ate = x/6

Now, remaining part = x-x/6 = (6x-x)/6 = 5x/6

Tanisha ate = (5x/6)/5 = 5x/(5×6) = x/6

Now, remaining part = (5x/6)-x/6 = (5x-x)/6 = 4x/6

Trisha ate = (4x/6)/4 = 4x/(4×6) = x/6

Now, remaining part = (4x/6)-x/6 = (4x-x)/6 = 3x/6

Karishmita ate = (3x/6)/3 = 3x/(3×6) = x/6

Now, remaining part = (3x/6)-x/6 = (3x-x)/6 = 2x/6

Palak and Aabha ate = (2x/6)/2 = 2x/(2×6) = x/6

HENCE THE CAKE WAS SHARED EQUALLY AMONG THE GIRLS

Hope this help you

Plz mark my answer as Brainliest

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