Question

Q13 The addition of numerator and denominator of a fraction is three less than twice the denominator. If the numerator and denominator are decreased by 1, the numerator becomes half the denominator. Find the fraction.​

Answer 1

Answer:

shoddy dust sh Soddy's Sd

Answer 2

Solution:

Let the numerator be x and denominator be y.

Therefore, fraction

$= \frac{x}{y}$

A/Q

$x + y = 2y - 3$

or

$x - y + 3 = 0 ...(i)$

And,

$x - 1 = \frac{1}{2} (y - 1)$

or

$2x - y - 1 = 0...(ii)$

Subtracting equation (1) from (2) , we get

$x - 4 = 0$

$= > x = 4$

From (i)

$4 - y + 3 = 0$

$= > y = 7$

Therefore, fraction

$= \frac{x}{y} = \frac{4}{7}$