Q13An object starts from rest and is uniformly accelerated so that its speed is 60 m/s after
20s. If it travels
with this speed for 40 s and is then brought to rest by a uniform retardation in 30 s. Sketch
the
velocity-time graph and calculate the acceleration, the retardation and the total distance
travelled.
Answers
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12
Answer:
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Explanation:
( i ) Given,
speed = 60 m/s
Time = 20 sec
speed = distance / time
60 = distance /20
60×20 = distance
1200 m/s = distance
(ii) Given,
speed = 40 m/s
Time = 30 m/s
speed = distance / time
40 = distance /30
40×30 = distance
1200 = distance
The total distance travelled = 1200+1200
= 2400 m/s
The total time taken = 20 +30
= 50
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