Q14 a) .Calculation of acceleration of the car : ( For motion from A to B ) initial velocity of the body at
time t1 ,u = 5m/s.
b). Find the value of distance covered by car
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Answer:
a) -5
b) 2.5m
Explanation:
Keys:
u= initial velocity
v=final velocity
a=acceleration
r=retardation
t=time
s=distance
u = 5m/s
t=1s
v =0
a=v-u \t
a= 0-5/1
a= -5 or r= 5
b) s=ut+1/2at² [ Second Equation of motion ]
s= 5×1+1/2×-5×1×1
s=5+(-2.5)
s=2.5 m
Thank You Guys!
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