Question

Q14. A cube of side 4 cm is cut into 1 cm cubes. What is the ratio of the surface areas of the
original cubes and cut-out cubes?
i. 1:3
ii. 1:2
iii. 1:6
iv. 1:4

Answer 1

Answer:

iv. 1:4

Step-by-step explanation:

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Answer 2

Answer:

Correct option is

C

1:4

(c) 1:4

Volume of cube a= a

3

Volume of the original cube having side of length 4 cm = 4

3

= 64 cm

3

Volume of the cut-out cubes with side of length 1 cm=1

3

Therefore, no .of cut-out cubes =

Volumeofasmallercube

Vol.oftheoriginalcube

=

1

64

=64

As, surface area of cube with side a= 6 a

2

Now, surface area of cut-out cubes = 64×6×(1)

2

cm

2

And surface area of the original cube = 6×4

2

cm

2

Therefore, the required ratio of surface areas of the original

cube and cut-out cubes =

64×6

6×4

2

=1:4