Question

Q14) A secondary cell has a terminal voltage of 2.10 V on open circuit. When
connected to 0.15 ohm resistance, the terminal voltage drops to 1.90 V. Calculate the
internal resistance of the cell. / एक माध्यमिक सेल में ओपन सर्किट पर 2.10 वी का टर्मिनल
वोल्टेज
1) 0.0157 ohm /0.0157 ओम
2) 0.0177 ohm /0.0177 ओम
3) 0.0187 ohm /0.0187 ओम
4) 0.0197 ohm/0.0197 ओम​

Answer 1

Answer:

Find the terminal potential difference in case of charging a battery.

According to question, it is the case of charging of battery. So, terminal potential difference is given by

TPD=V−VR =E+Ir=2+(4×2) =10V....(i)

Again, VR−VQ =IR=4×4=16V....(ii)

From Eqs. (i) and (ii), we get

VV −VR +VR −VQ =10+16⇒VP −VQ =26V

solution

Explanation:

so the answer is 26 V