Question

Q14. If sum of zero is -2 and product of zero is 3 then polynomial is given by
a)
x2 – 2x + 3
b)
x2 – 2x - 3
C
4x2 + 8x + 12 d) none
AFC​

Answer 1

Answer:

i thik D.

becuse x

$x {}^{2} - (sum \: of \: the \: zeroes)x + (product \: of \: the \: zeroes)$

x2-(-2x)+3

x2+2x+3

it is the answer

but there is no. option like this

so. answer is D

Answer 2

correct option is option (c) :- 4x² + 8x + 12

Given :-

the sum of zero = -2

product of zero = 3

$\bf \: let \: first \: zero \: = \alpha \\ </p><p>\bf \: second \: zero = \beta$

as we know that :-

$\bf \: \alpha + \beta = \dfrac{ - b}{a} \\ \\ \sf \: \alpha + \beta = - 2 \: \: \: \: \: (given) \\ \\ \therefore \: \: \sf \: - 2 = \dfrac{b}{a} \\ \\ \bf \alpha \times \beta = \dfrac{c}{a} \\ \\ \sf \: \alpha \times \beta = 3 \: \: \: \: \: \: \: (given) \\ \\ \therefore \: \: \sf \: 3 = \dfrac{c}{a}$

here,

a = 1

-b = -2

∴ b = 2

c = 3

polynomial = ax² + bx + c

put the values of a, b, & c we get --

x² + 2x + 3

multiply by 4 in polynomial we get --

4x² + 8x + 12

hence, polynomial = 4x² + 8x + 12