Question

Q14. If1 is one of the zeroes of the polynomial x2+x+k, then the value of K is.
2
b.
d​

Answer 1

Answer:

p(x) = x²+x+k

given, 1 is the zero of polynomial

since 1 is the zero , p(1) = 0

substitute 1 in p(x)

p(1) = (1)²+1+k = 0

1 +1+k = 0

2+k = 0

k = -2

Answer 2

Answer:

k = -6

Step-by-step explanation:

p(x) =x^2 + x + k

g(x) = 2

therefore x = 2

puting the valur in p(x)

(2)^2 + 2 + k = 0

4 + 2 + k = 0

6 + k = 0

● k = -6