Question

Q14. Rectangle ABCD is an isos es
trapezium I(AB)=13cm, seg AP
perpendicular to seg DC and is
perpendicular to DC: I(DP)= 5 n.
Distance between two paral sides
is 12cm . Find the area of qurilateral
ABCD.

● 42 sq.cm

●216cm

●42cm

● 216sq.cm​

Answer 1

Step-by-step explanation:

Answer

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Length of PQ=7 cm

Length of PM= distance between two parallel sides =4 cm 

Length of SM=3cm 

Length of SR=SM+MN+NR 

because PQRS is isosceles trapezium, 

so, SR=NR=3cm and MN=PQ=7cm 

so, Length of SR=3cm +7cm +3cm =13cm

Now, area of PQRS=21(PQ+SR)×PM

=21(7+13)×4

=20×2=40sq.cm

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