Question

Q14 Two trains X and Y are running on parallel tracks with a speed of 72km/h and 54km/h
respectively
The driver of train X applies the brake and it comes to a stop in 10seconds. While the driver
of train Y
applies the brake and the train retards uniformly before coming to rest in 15 seconds. Plot
distance-
time graphs for both the trains. Also, calculate the distance travelled by each train after the
brakes were
applied
Look

Answer 1

ANSWER:

Here,

is your answer

The initial velocity is given by u=72km/hr

To convert it into SI system ie. (m/s), multiply it with 5/18.Therefore,

u = 72*(5/18)=20 m/s

Final velocity = 0 m/s (Since the train comes into rest)

Acceleration, a= - 0.2 m/s^2

We have to find the distance s.

So by Third equation of motion,

v^2 = u^2 + 2aS

S= (v^2-u^2)/2a

= (0-400)/-0.4

=1000 m

ie, the distance travelled by the train before it come to rest is 1000 m

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