Question

Q14The auto mobile vehicle has a mass of 1500 kg .what must be the force between the

vehicle and the road if the vehicle is to be stopped with a negative acceleration of 1.7

m/s2​

Answer 1

Given:-

• Mass of automobile , m = 1500kg

• Acceleration ,a = -1.7m/s²

To Find:-

• Force between Road and Vehicle ,F.

Solution:-

Force is the product of mass and acceleration

•F = m×a

Substitute the value we get

→ F = 1500×(-1.7)

→ F = -2550N

Here negative sign show the force acting in opposite direction.

∴ The Force between Road & Vehicle is 2550 Newton

Additional Information !!

• Product of mass and acceleration is called force.

•A push or pull of an object is called force.

•SI unit of Force is Newton.

• It is denoted by N.

• Force is vector Quantity i.e., both Magnitude and direction.

• Mathematical term

• Force = Mass×Acceleration

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore \: F = - 2550N }}$

$\orange{\bold{\underline{\underline{Step\: - \:by\:-\:step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies \:mass = 1500kg \\ \tt: \implies \: acceleration = -1.7m/{s}^{2}$

$\red{\underline \bold{To\:find :}} \\ \tt: \implies Force\:required = ?$

• According to the given question:

$\bold{As\:we\:know\:that:}$

$\tt: \implies Force = mass * acceleration \\ \\ \tt: \implies Force = 1500kg * (- 1.7)m/{s}^{2} \\ \\ \green{\tt{: \implies Force = - 2550N}}$

• Additional Information:

$\tt: \implies Force\: is\: an\: external\: effort\: \\ \tt \quad \quad in\: the \:form \:of \:push\: or\: pull \\ \\ \tt: \implies Force\: may\: or\: may \:not:- \\ \tt \quad \quad \bullet Increase \:or \:decrease\: the\: velocity\: \\ \quad \quad \tt of \:an \:object \: \\ \tt \quad \quad \bullet Change \:the\: state\: from \:motion \:to\:\\ \tt \quad \quad rest\: or\: from \:rest\: to\: motion \\ \tt\quad \quad \bullet Change \:the \:shape\: and \:size\: of\: an\:\\ \tt \quad \quad object \\ \\ \tt: \implies Force\: is\: a \:vector\: quantity\: -\: It \\ \quad\tt \quad \quad \:has\: both \:magnitude\: and\: direction \\ \\ \tt: \implies Force \:=\: Mass\: *\: Acceleration$