Question

Q15. 300J of work is to be done in lifting a
bag of mass 5kg (3)
in weight up to a height of 4m from the
ground. What will be
the acceleration with which the bag
was revised? (take
g=10m/s2]​

Answer 1

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Answer 2

Explanation:

Given, mass, m = 5 kg, work, W = 300 J h = 4 m, g = 10 ${{ms}^{-2}}$

Work done, W = mgh + mah = m(g + a)h =

300 = 5 x (10 + a) x 4

=> 300 = 20(10 + a)

10 + a = 300/20 = 15

a = 15-10 = 5 ${{ms}^{-2}}$

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