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Q15
एक लोहार के पास 36 सेंटीमीटर व्यास Ablacksmith have big iron ball of diameter
36cm. He first formed four identical
का एक लोहे का गोला है वह इससे
cylindrical rod out of this ball for some
मरम्मत के काम के लिए 4बेलनाकार रॉड
construction work. When he finished his
बनाता है, फिर काम के उपरांत वह इन work with the cylindrical rod, he again
सबको मिलाकर कुछ छोटे गोले बनाता है | mixed all the iron rod and formed some
जिनकी त्रिज्या 9 सेंटीमीटर है
identical small balls, each of radius 9cm.
Answers
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Given :-
- Diameter of iron ball = 36 cm.
- Radius of small balls = 9 cm.
To Find :-
- Number of small ball formed by blacksmith ?
Solution :-
Let us assume that, n number of small ball formed by blacksmith.
so,
→ Volume of iron ball = n * volume of each small ball .
→ (4/3) * π * (R)³ = n * (4/3) * π (r)³
(4/3) and π will be cancel from both sides,
→ (R)³ = n * (r)³
→ (36/2)³ = n * (9)³
→ (18)³ = n * (9)³
→ 18 * 18 * 18 = n * 9 * 9 * 9
→ n = 2 * 2 * 2
→ n = 8 (Ans.)
Hence, the number of small ball formed by blacksmith are 8 .
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