Question

Q15 If a+b+c = 6 and ab+bc+ca = 11, find a ^2+b^2+c^2​

Answer 1

Answer:

14

Step-by-step explanation:

Given :

a + b + c = 6

Squaring on both sides

=> ( a + b + c )² = 6²

Using algebraic identity ( a + b + c) ² = a² + b² + c² + 2( ab + bc + ca)

=> a² + b² + c² + 2( ab + bc + ca ) = 36

=> a² + b² + c² + 2( 11 ) = 36

=> a² + b² + c² + 22 = 36

=> a² + b² + c² = 36 - 22

=> a² + b² + c² = 14

Therefore the value of a² + b² + c² is 14