Q15) In given figure,<OAB=75,<OBA=55° and <OCD=100° then ODC=?
1. 20°
2. 25°
3. 30°
4. 35°
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Answer:
in ∆AOB
ANGLE AOB=180°-75°-55°=50°
ANGLE AOB=ANGLE COD=50°[opposite angle ]
now in ∆COD
ANGLE ODC=180°-100°-50°=30°
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