Question

Q15)lf (x/y+y/x)=-1 where x,y is not
equal to zero ,then the value of x3-y3is​

Answer 1

Answer:

0

Step-by-step explanation:

Given that,

x/y + y/x = -1

To find the value of x^3 - y^3.

Solving further, we get,

$= > \frac{x}{y} + \frac{y}{x} = - 1 \\ \\ = > \frac{{x}^{2} + {y}^{2}}{xy} = - 1 \\ \\ = > {x}^{2} + {y}^{2} = - xy$

Now, we know that,

${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} + xy)$

Substituting the values, we get,

$= > {x}^{3} - {y}^{3} = (x - y)(xy - y) \\ \\ = > {x}^{3} - {y}^{3} = (x - y) \times 0 \\ \\ = > {x}^{3} - {y}^{3} = 0$

Hence, the required value is zero.

Answer 2

x3-y3=0

Hopefully it’s helpful for you
Thanks