Q15 lines and angles do step by step will marked as brainliest
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Step-by-step explanation:
Ray BO is the bisector of angle CBP
Therefore,angle CBO = 1/2of angle CBP
= 1/2(180-y)
= 90-y/2 .........(1)
Similarly, ray OC is the bisector of angle BCQ
Therefore,angle BCO = 1/2 of angle BCQ
= 1/2(180-z)
= 90-z/2 ............(2)
In triangle BOC, angle BOC+BCO+CBO = 180 ........(3)
Substituting (1,2,3) you get
Angle BOC+90-z/2+90-y/2 = 180
Angle BOC = z/2+y/2
= 1/2(y+z)
But,x+y+z=180 (angle sum property)
y+z=180-x
Angle BOC=1/2(180-x)
= 90 - x/2
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