Question

Q150:- Find the equation of the line passing through the point (2, 3) and parallel to the join of the points
(4, 2) and (-2, 6).​

Answer 1

Answer:

The slope of the line joining points: (1, 2) and (-1, 5) is:

m = (2 - 5)/(1 + 1) = -3/2

Equation of the line joining points: (1, 2) and (-1, 5):

y - 5 = (-3/2)(x + 1)

y - 5 = (-3/2)x - 3/2

y = (-3/2)x + 7/2

Equation of the line passing through the point(2, -3) and parallel to the line joining points: (1, 2) and (-1, 5):

y + 3 = -3/2(x - 2)

y + 3 = (-3/2)x + 3

y = -(3/2)x

Here is the graph:

Answer 2

Answer:

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Step-by-step explanation:

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