Q150:- Find the equation of the line passing through the point (2, 3) and parallel to the join of the points
(4, 2) and (-2, 6).
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The slope of the line joining points: (1, 2) and (-1, 5) is:
m = (2 - 5)/(1 + 1) = -3/2
Equation of the line joining points: (1, 2) and (-1, 5):
y - 5 = (-3/2)(x + 1)
y - 5 = (-3/2)x - 3/2
y = (-3/2)x + 7/2
Equation of the line passing through the point(2, -3) and parallel to the line joining points: (1, 2) and (-1, 5):
y + 3 = -3/2(x - 2)
y + 3 = (-3/2)x + 3
y = -(3/2)x
Here is the graph:
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