Question

Q16. ABCD is a trapezium such that AB//CD, angle A: angle D=2:1, angle B: angle C=7:5. Find all the angles of trapezium.

Answer 1

ABCD is a trapezium....given
AB||CD...given
Let angle A=2x,B=7x,C=5x and D=x...from given and say
Therefore,AB||CD with transversal BC
Therefore angle ABC+angle DCB=180°...interior angles
i.e. angle C+angle B=180°
therefore 5x+7x=180°
12x=180°
x=15
therefore angle A=2x=2×15°=30,B=7x=7×15=105°,C=5x=5×15=75° and D=x=15°


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Answer 2

Answer:ABCD is a trapezium....given

AB||CD...given

Let angle A=2x,B=7x,C=5x and D=x...from given and say

Therefore,AB||CD with transversal BC

Therefore angle ABC+angle DCB=180°...interior angles

i.e. angle C+angle B=180°

therefore 5x+7x=180°

12x=180°

x=15

therefore angle A=2x=2×15°=30,B=7x=7×15=105°,C=5x=5×15=75° and D=x=15°

Step-by-step explanation: