Q16. If a+ b + c = 0, prove that: 2/+ 2/+ 2/= 3
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Answer:f a b c are all non zero and a+b+c=0 prove that a2/bc+b2/ca+c2/ab=3
a²/bc + b²/ca + c²/ab = 3
Multiplying by abc both sides
=> a³ + b³ + c³ = 3abc
=> (a+ b)³ - 3ab(a+b) + c³ = 3abc
as we know that a + b + c = 0
=> a + b = -c
=> (-c)³ - 3ab(-c) + c³ = 3abc
=> -c³ + 3abc + c³ = 3abc
=> 3abc = 3abc
Step-by-step explanation:
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