Question

Q16. Out of the elements H(1), Be(4), Na(11) and Mg(12).
i. Write the pair of elements having similar chemical properties.
ii. State the group number of each pair,
iii. Name one another element belonging to each of these groups.
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Answer 1

Answer:

1. Na and H ......Be and Mg

2. Na and H group number =1

Be and Mg group number =2

3. 1. H,Li,Na,K,Rb,Cs,Fr

2. Be,Mg,Ca,Sr,Ba,Ra.

Explanation:

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Answer 2

Answer with Explanation:

Electronic configuration of H(1)=$1s^1$

Atomic number of Na=11=$1s^22s^22p^63s^1$

H and Na have 1 electron in outermost shell.Therefore, both elements belong to group 1.

H(1) and Na(11) belongs to group 1

Electronic configuration of Be=$1s^22s^2$

Electronic configuration of Mg(12)=$1s^22s^22p^63s^2$

Valency of of both elements Be and Mg is 2.

Therefore, both elements belongs to group 2.

i.H and Na

Be and Mg

ii.H and Na : group 1

Be and Mg: group 2

iii.Li(group 1)

Ca(group 2)

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