Question

Q16. The age of A is five years more than that of B, 5 years ago, the ratio of
was 3:2. Find their present ages.​

Answer 1

EXPLANATION.

Age of A is five more than that of B

=> Let the age of A = ( x + 5 ) years.

=> Let the age of B = x years.

5 years ago,

Present age of A = ( x + 5 ) - 5 = x years.

Present age of B = ( x - 5 ) years.

The ratio of was = 3:2.

=> x / x - 5 = 3/2

=> 2x = 3 ( x - 5 )

=> 2x = 3x - 15

=> x = 15 years.

Therefore,

Present age of A = ( x + 5 ) = ( 15 + 5 ) = 20 years.

present age of B = x = 15 years.

Answer 2

⚜ Given :-

• The age of A is five years more than that of B, 5 years ago, the ratio of was 3:2.

⚜ To Find :-

• Their Present Ages.

⚜ Solution :-

☯️ Let,

The Age Of B = x.

The Age Of A = x + 5.

Before 5 Years,

The Age Of B = x - 5.

The Age Of A = x.

According To The Question, The Equation :-

⇒ x/x - 5 = 3/2.

⇒ 2(x) = 3(x - 5).

⇒ 2x = 3x - 15.

⇒ 2x - 3x = -15.

⇒ -x = -15.

⇒ x = 15.

So,

☘ Present Age Of A = 20 Years.

☘ Present Age Of B = 15 Years.