Question

Q17) A bullet of mass 10 g is moving with a speed of 200 m/s. What is the kinetic energy of the bullet?
​

Answer 1

$\huge\mathfrak{\color{orange}{\underline {\underline{Answer :-}}}}$

Mass of the bullet, m = 10g

$= \frac{10}{1000} kg = 0.01kg$

Speed of the bullet, v = 200 m/s

Kinetic energy of the bullet, KE = $\frac{1}{2} mv^{2}$

$= \frac{1}{2} \times 0.01 \times 200 \times 200 = 200j$

Answer 2

Answer:

Mass of the bullet, m = 10g

10upon1000kg=0.01kg

Speed of the bullet, v = 200 m/s

Kinetic energy of the bullet, KE = 1upin2mv2

1upon2*0.01*200*200=2000j

so the answer is 2000j..

Explanation: