Q17 answer please now
Attachments:
Answers
Answered by
0
1/2*AB*AC*Sin A
Now, Area of trianlge ABC = Area of ADB + Area ADC
=> (1/2) * AB * AC * sinA = (1/2) * AB * AD * Sin(A/2) + (1/2) * AC * AD * Sin(A/2).
=>12 sin60° = 4*AD*sin30° + 3*AD*sin30°
=> 12√3/2= (7/2)*AD.
Hence, AD = 12√3/7.
please please please mark brainiest
it took quite a while to type all this. please
Now, Area of trianlge ABC = Area of ADB + Area ADC
=> (1/2) * AB * AC * sinA = (1/2) * AB * AD * Sin(A/2) + (1/2) * AC * AD * Sin(A/2).
=>12 sin60° = 4*AD*sin30° + 3*AD*sin30°
=> 12√3/2= (7/2)*AD.
Hence, AD = 12√3/7.
please please please mark brainiest
it took quite a while to type all this. please
fkdjfjf:
It is wrong answer
Similar questions
Environmental Sciences,
7 months ago
Math,
7 months ago
Physics,
1 year ago
CBSE BOARD X,
1 year ago