Question

Q17. Calculate maximum power when
Thevenin's voltage and resistance is
2V and 5.33ohms respectively.​

Answer 1

Given : Thevenin's voltage and resistance is  2V and 5.33ohms respectively.​

To Find : Calculate maximum power

Solution:

maximum power when Load resistance = Thevenin  resistance

Hence Total Resistance = Load Resistance + Thevenin  resistance

= 2 Thevenin  resistance

Current  =  Thevenin's voltage / 2 Thevenin  resistance

Power transferred to Load =  I² * Load resistance

= ( Thevenin's voltage / 2 Thevenin  resistance)²  * Load resistance

=  ( Thevenin's voltage / 2 Thevenin  resistance)²  * Thevenin  resistance

= Thevenin's voltage²/4 Thevenin  resistance

 VTh = Thevenin's voltage

Thevenin  resistance =  RTh

Max Power transferred to Load =  VTh² / 4RTh

VTh = 2 V

RTh  = 5.33 Ω

Max Power transferred to Load =  2² / 4(5.33)

= 1/5.33

= 0.1875W

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Answer 2

The maximum power is 0.188 W

Step-by-step explanation:

Given:

Thevenin's Voltage $V_{Th}=2$ V

Thrvenin's resistance $R_{Th}=5.33$ ohms

To find out:

Maximum power

Solution:

We know that

Maximum power transferred is given by

$P=\frac{V_{Th}^2}{4R_{Th}}$

$\implies P=\frac{2^2}{4\times 5.33}$

$\implies P=0.188$ W

Hope this answer is helpful.

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