Question

Q17. find the length of the hypotenuse of a right isosceles triangle whose area is 961 sq. cm.
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Answer 1

Answer:

Length of hypotenuse is x

Area is $961^{2} cm$

Area of triangle= $\frac{1}{2}$×b×h

so,

961=$\frac{1}{2}$×b×b    (as isosceles triangle, the two sides except the hypotenuse are same)

961×2=$x^{b}$

1922=$b^{2}$

$\sqrt{1922}$=b

43=b (approx.)

so, using Pythagoras theorem we can find hypotenuse

$43^{2}$+$43^{2}$= $x^{2}$

3698=$x^{2}$

$\sqrt{3698\\}$=$x^{2}$

60=x (approx.)