Question

Q17. Force between two charges
separated by a certain distance in air is F.
If each charge is doubled and distance
between them is also doubled, force
would be​

Answer 1

Answer:

Force doesn't changed

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Answer 2

Question:

Force acting between two charges separated by a certain distance in air is F. If each charge is doubled and distance between them is also doubled, force would be?

Answer:

Let q1 and q2 be two charges separated by a distance d.

And the force acting between two charges is F as given in the question.

$\huge F= K\frac{q_1q_2}{d^2}$

As per the question, each charge is doubled and distance is also doubled, then, $q_1$ will be $2q_1$ and $q_2$ will be $2q_2$ and distance will be 2d.

Now, the force acting between them is (let it be F1) :

$F_1 = K \frac{2q_1 \times 2q_2}{(2d)^2} \implies K \frac{4 q_1q_2}{4d^2} \implies K \frac{\cancel{4} q_1q_2}{\cancel{4}d^2} \\\\ \implies K\frac{q_1q_2}{d^2} = F$

Hence, we can see that there's no change in the Force, it would be the same.