Question

Q17. In fig. ABC is a quadrant of a circle of radius 14cm and a semicircle is drawn with BC as
diameter. Find the area of the shaded region.​

Answer 1

Step-by-step explanation:

Area of shaded region = Area of △ABC + Area of semicircle with diameter BC − Area of quadrant ABC

∴ Area of △ABC =

2

1

×14×14=98cm

2

In △ABC, by Pythagoras theorem,

BC=14

2

∴Area of semicircle with diameter BC=

2

π×r

2

=

2

1

×

7

22

×7×7×2=154cm

2

Area of quadrant ABC =

4

π×r

2

=

4

1

×

7

22

×14×14=154cm

2

∴ Area of shaded region =98+154−154=98cm

2