Q17. The area of triangle with given
two sides 18 cm and 10 cm
respectively and its perimeter equal
to 42 cm is :
Answers
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Step-by-step explanation:
The third side, c = x cm
a = 18 cm
b = 10 cm
perimeter = a + b + c
42 = 18 + 10 + x
42 = 28 + x
42 - 28 = x
14 = x
s = a+b+c/2
s = 18+10+14/2
s = 21 cm
area = √s(s-a)(s-b)(s-c)
= √21(21-18)(21-10)(21-14)
= √21(3)(11)(7)
= √3X7X3X11X7
= √3X7X11
= √231
= 15.1986842 cm
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