Science, asked by vaibhavsingh66, 1 year ago

Q18.A particle is moving along a straight line an
its position is given by the relation x =
15t +40)m. Find (a) The time at which velocity is
zero.
(b) Position and displacement of the particle at
that point. time
Tire
(c) Acceleration for the particle at that line.​

Answers

Answered by daring7devil
1

Answer:

t = x^1/2 + 3

√ x = t - 3

sq both sides

x = ( t - 3 )^2

x = ______(1)

we know

differentiation of distance w.r.t time ,give velocity

so

d (x) / dt = 2 t - 6

v = 2 t - 6

v = 0 ,given

t = 3 second

from eq 1

x = t^2 - 6t + 9

x = 3 × 3 - 6 × 3 + 9

x = 9 - 18 + 9

x = 0

SO DISPLACEMENT WILL BE ZERO

HOPE HELPED

Read more on Brainly.in - https://brainly.in/question/4074438#readmore

Explanation:

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