Q18. A train covers a distance
of 90 km in 90 minutes.. Find
the time taken by the train to
cross an electric pole if the
length of the train is 300m.
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Let the length of the bridge be x metres and length of the first train at 90 km/hr be y metres
Then (x+y)=[(90×
18
5
)×36] m =900 m
The second train crosses the bridge by covering distance of [x+(y−100)]m at the rate of 45 km/hr
12.5 m/s i.e. 800 m at 12.5 m/s (∵x+y=900 m)
Time taken by the second train to cross the bridge =
12.5
800
sec =64 seconds
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