Math, asked by kunalika, 10 months ago

Q18 Find sum of multiples of 4(first 40 terms)

Answers

Answered by ijazuddinsaifi396

1

Answer:

S40 =40/2+[2a+(n-1) d]

Step-by-step explanation:

4[S40] =4(20+(2a+19 d)

Answered by neharathore04

0

Answer:

SN=n/2(2a+(n-1)d)

Step-by-step explanation:

40/2(8+(39)4)=3280

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