Math, asked by siddhishetye4, 12 hours ago

Q18. If tan²theta = 1 - a², then sec theta + tanº theta*cosec theta= (k-a²) 3/2 then the value of k is​

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Answers

Answered by ethicalhacker7049
0

Answer:

We have

secθ+tan

3

θcosecθ

=secθ[

secθ

secθ+tan

3

θcosecθ

]

=secθ[1+tan

3

θ⋅

sinθ

cosθ

]

=secθ[1+tan

3

θ×cotθ]

=

1+tan

2

θ

[1+tan

2

θ]

=[1+tan

2

θ]

3/2

=[1−(1−a

2

)]

3/2

=(2−a

2

)

3/2

 

[∵tan

2

θ=1−a

2

]

Step-by-step explanation:

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