Question

Q18. In the circuit given below find the values of a) Capacitive reactance b) Inductive reactance c) impedance of the circuit d) phase difference between voltage and current. e) Peak value of current in the circuit. mm lон 2017 5002 V=200 Sin loot​

Answer 1

Answer:

so the answer is

Explanation:

A: We can calculate the capacitive reactance X of a capacitor C using the following equation: X = 1 / (2 * π * f * C) .

b: If the reactance releases energy in the form of a magnetic field, it is called inductive reactance whereas if the reactance releases energy in the form of an electric field, it is called capacitive reactance

C: The magnitude of the impedance Z of a circuit is equal to the maximum value of the potential difference, or voltage, V (volts) across the circuit, divided by the maximum value of the current I (amperes) through the circuit, or simply Z = V/I. The unit of impedance, like that of resistance, is the ohm

D:The phase difference between current and voltage in an AC circuit is π4 radian.

E: According to the question V=200sin314t and R=10Ω

comaring it with original equation we get ,V

m

=200V

(1} rms voltage , V

rms

=

2

V

m

=0.707×200=141.4V

(2)rms current , I

rms

=

R

V

rms

=

10

141.4

=14.14A

(3)power dissipate ,P=V

rms

I

rms

cosθ

here cosθ is power factor which is equal to 1 for pure resistive circuit since voltage and current are in same phase,

p=141.4×14.14=1999.69≃2000W