Question

Q18
The acceleration due to gravity on the surface of a satellite is 1.5 ms 2. The time period of a simple pendulum on it, if its time period on the earth is t , will be
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Answer 1

)

ANSWER

Acceleration due to gravity on the surface of moon, g

′

=1.7ms

−2

Acceleration due to gravity on the surface of earth, g=9.8ms

−2

Time period of a simple pendulum on earth, T=3.5s

T=2π

g

l

where,

l is the length of the pendulum

∴l=

(2π)

2

T

2

×2

=

4×(3.14)

2

(3.5)

2

×9.8m

The length of pendulum remains constant

On moon's surface, time period, T

′

=2π

g

′

l

=2π

1.7

4×(3.14)

2

(3.5)

2

×9.8

=8.4 s

Hence, the time period of the simple pendulum on the surface of moon is 8.4 s.