Question

Q18 URGENT
Please give correct answer please i will mark brainliest if answer is correct
thanks

Answer 1

Answer:

B Answered

Explanation:

please mark as brilliant

Answer 2

Answer:

d) 6×6.022×10²³ ions of Cl⁻ will be releasedon complete dissociation of 267g of AlCl₃ in the water.

Explanation:

The given compound is AlCl₃

The Molecular weight of  AlCl₃= Atomic weight of Al+3×Atomic weight of Cl

                                                   =27+3×35.5

                                                    =27+106.5

                                                     =133.5g

Given 267g of AlCl₃ is completely dissolved

Number of moles of AlCl₃=$\frac{weight of AlCl_{3} }{Molecular weight of AlCl_{3} }$

                                           =$\frac{267}{133.5}$

                                            =2moles

The Reaction for Dissociation of 1 mole of AlCl₃ is as follows

AlCl₃------>Al³⁺ +3Cl⁻

Thus when 1 mole of AlCl₃ is dissolved it releases 3 moles of Cl⁻ ions.

In the given question it is 2 moles so total 6 moles will be released.

It is asked the number of ions. So, multiply it with the Avogadro's Number to get the answer.

Number of Cl⁻ ions=6×$N_{A}$

                                =6×6.022×10²³