Question

Q19 ) (1-i) ^4in the form of a+ib=​

Answer 1

Answer:

1−i)

4

=[(1−i)

2

]

2

=[1

2

+i

2

−2i]

2

=[1−1−2i]

2

=(−2i)

2

=(−2i)×(−2i)

=4i

2

=−4,[∵i

2

=−1]

=a+ib, where a=−4, and b=0