Q19
A body is projected at an angle 60° with the horizontal with kinetic energy K. When the velocity makes an angle 30° with the horizontal, the kinetic energy
of the body will be
a k/2
b к/з
c 2K/3
d зк/4
Answers
Answered by
0
Answer:
Given,
1/2xm u² = k
Vx = Vcos 30°
Ucos 60°
Ucos 60° = Vcos 30°
V = u/√3
Ke = 1/2xmxv²
Ke = 1/2m (u/√3)
Ke = 1/2m u²x1/3
So the answer is (B) k/3
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