Math, asked by rajannagowdru86, 2 months ago

Q19.Hari and Raj are software engineers. They are friends working in a
Multinational company. Ratio of their present ages are 4: 5. Eight
Years from now their ages are will be 5: 6.
(i) Find the present age of Hari
(a) 33 years
(b) 32 years
(c) 34 years
(d) 40 years
(ii) Find the present age of Raj
(b) 35 years
(c) 38 years
(a) 40 years
(d) 45 years
(iii) The difference between their ages
(c) 10 years
(d)12 years
(a) 9 years
(b) 8 years​

Answers

Answered by pk011898
0

Answer:

Let their Hari's present age be 4x

then, Raj's present age be 5x

A/q

4x+8/5x+8 = 5/6

= 6(4x+8) = 5(5x+8)

= 24x + 48 = 25x + 40

= 24x -25x = 40 - 48

= -x = -8

= x = 8

Hari's present age = 4× 8= 32

Raj's present age = 5× 8 = 40

Difference between their ages = 40-32 = 8

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