Question

Q19Find the ratio in which x

axis divides the line segment

joining points A (-3 ,10) and B(6 ,– 8).Also find the point of

intersection.​

Answer 1

Answer:

Solution :-

Given x-axis divide the segment joining points

(2,−3) and (5,6)

Let the ratio be k:1

then x =

m

1

+m

2

m

1

x

2

+m

2

x

1

y=

m

1

+m

2

m

1

y

2

+m

2

y

1

=0

⇒

k+1

6k−3

=0

⇒6k=3

⇒k=

2

1

the ratio is 1:2

Answer 2

Step-by-step explanation:

Let the required ratio be λ;1. Then, the coordinates of the point of division are,

R( 6λ-3 , -8λ+10 )

( λ+1 λ+1 )

But, it is a point on x-axis on which y-coordinates of every point is zero.

∴ 6λ-3

λ+1

=0⇒λ= 1/2

Thus,the required ratio is 1/2 : 1 or, 1:2

Putting λ=1/2 in the coordinates of R, we find that its coordinates are (0,6)