Question

Q1A policeman and a thief are equidistant from the jewellery box. Upon considering jewellery box as origin the position of policemen is (0 5) if the coordinate of the position of thief is mirror image
With Diagram ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

Given position of jewel box as original, O(0,0).

Let the position of policeman be P(0,5).

Given that the ordinate of position of the thief is zero.

Let the abscissa of the position of the thief be x.

Hence coordinates of position of thief be Q(x,0).

Given that point P and Q are equidistant from the point O.

That is OP=OQ ....(1)

Since the distance between two points is

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

OP=

(0−0)

2

+(0−5)

2

=5

OQ=

(x−0)

2

+(0−0)

2

=x

Equation (1), becomes x=5

Thus the coordinates of the position of thief is (5,0)