Chemistry, asked by riyag5366, 9 hours ago

Q1What mass of ammonium nitrate is required to make a saturated solution of ammonium nitrate in 150g of water at 298 K? [The solubility of this salt at the given temperature is 32g]. *

Answers

Answered by 3v3rocketmail
0

Answer:

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Answered by thakrepayal25
0

given : solubility of ammonium nitrate at 298K is 32g

by statement , we can say that

using unitary method

100g of water at 298 K contain 32 g NH_{4} NO_{3}

therefore ,150g water at 298 K contain NH_{4} NO_{3}  = 32/100 x 150

= 48 g

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