Question

Q1Write the solution of 3x+y= 8
Q2if x= -1 and y=2 is a solution kx +3y=7

Answer 1

Q 2 kx+3y=7

k(-1)+3(2)=7


k(-1) + 6=7

k(-1)= 6-7

k(-1)=1
k= 1 ×-1
k= -1

Answer 2

1)
$3x + y = 8$
$3x = 8 - y$
$x = 8 - y \div 3$

2)
$kx + 3y = 7$
$k( - 1) + 3(2) = 7$
$- k + 6 = 7$
$- k = 7 - 6$
$- k = 1$
$k = - 1$
the value of k is -1