Question

Q2.
2. If one zero of the quadratic
polynomial (k-1)x2 +kx +1 is - 3, then the
value of k is

Answer 1

Step-by-step explanation:

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Answer 2

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We can substitute it by;

$p(x) = {(k - 1)}^{2} + kx + 1$

So,

$p( - 3) = 0$

$p( - 3) = (k - 1) {( - 3)}^{2} k( - 3) + 1 = 0$

$9k - 9 - 3k + 1 = 0$

$6k - 8 = 0$

$6k = 8$

$k = \frac{8}{6}$

$k = \frac{4}{3}$

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