Q2. A bag contains 5 red marbles, 8 white marbles, 4 green
marbles. What is the probability that if one marble is taken
out of the bag at random is not green
Answers
Answer:
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Step-by-step explanation:
(i) Red ?
Total number of marbles = 5+8+4 = 17
Number of marbles which are white = 5
P (marble taken out is red) = Number of marbles which
are red /Total number of marbles = 5/17
(ii) White ?
Total number of marbles = 17
Number of marbles which are white = 8
P (marble taken out is white) = Number of marbles which are white /Total number of marbles = 8/17
(iii) Not green ?
P(marble taken out is not green) = P(marble taken out is white)+ P(marble taken out is red) = 8/17+5/17 = 13/17
P (marble taken out is not green) = 1- P(marble taken out is green)
Total number of marbles = 17
Number of marbles which are green = 4
P(marble taken out is green) = Number of marbles which are green/Total number of marbles = 4/17
P(marble taken out is not green)
= 1-P(marble taken out is green)
= 1-4/17
= 17-4/17
= 13/17
Answer:
No. of red marbles =5
No.of white marbles = 8
No.of green marbles = 4
Total no of marbals = 5+8+4= 17
p(not green) = 1 - p(not green)
= 1 - 4/17
= 17-4
17
=13/17