Q2. A body travels a distance of 3 km towards East, then 4 km towards North and finally 9 km towards East: (1) What is the total distance travelled? (2) What is the resultant displacement?
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Given A body travels travels a distance of 3km towards East, then 4km towards North and finally 9 km towards East.
So total distance travelled by body is length of the path traversed =AB+BC+CA=(3+4+9)km=16km
Displacement is the shortest path between source and destination.
So in this case it is Path OC.
If we see the diagram, as ABCD is a rectangle.
AB=CD=4KM
BC=AD=9KM
OD=OA+AD=3+9=12KM
Consider right angle triangle ODC
By Pythagoras theorem,
OC²=OD²+CD²=12²+4²
=144+16
OC²=160KM
OC=√160=12.65Km
Hence displacement is 12.65Km
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