Question

Q2.) A car accelerates uniformly from 0 to
72 km/h in 11.5 seconds?
a.) What is the acceleration of the car
m/s²?
b) What is the position to of the car
by the time it reaches the
velocity of 72 km/h?


Note : please give explanation
​

Answer 1

Initial velocity = u = 0m/s

Final velocity = v = 72km/hr = 72*5/18 m/s = 20m/s

Time taken = t = 11.5s

a = Change in velocity/Time taken = (v-u)/t

a = (20-0)/11.5 = 20/11.5 = 200/115 m/s²

v² = u² + 2as

(20)² = (0)² + 2*200/115*S

400 = 400/115 * S

S = 400 * 115/400 = 115m

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